User's Online Presence

Hi,
Correct me if i’m wrong but the only way to know if a user is online or offline is by using this code as mentioned in the doc

ArrayList<String> userIds = new ArrayList<>();
userIds.add("Jeff");

ApplicationUserListQuery listQuery = SendBird.createApplicationUserListQuery();
listQuery.setUserIdsFilter(userIds);

listQuery.next(new UserListQuery.UserListQueryResultHandler() {
    @Override
    public void onResult(List<User> list, SendBirdException e) {
        if (e != null) { 
            // Handle error.
        }

        // list.get(0) = 'Jeff' 
        if (list.get(0).getConnectionStatus() == User.ConnectionStatus.ONLINE) {
            // 'Jeff' is currently online.
            // User.ConnectionStatus consists of NON_AVAILABLE, ONLINE, and OFFLINE.
            ... 
        }
    }
});

and if i need a more realtime approach then i need to follow this as mentioned in the doc

it says that i need to have a mechanism wherein i’d be calling the next() function periodically, perhaps in intervals of one minute or more.

My question is how can i achieve the realtime-ness if i’ll be hitting every 1 minute or so, a user can switch back and forth from the app multiple times in a span of a minute and i won’t be notified of those events.